(11x+2x^2)-(-7x-3x^2=+4)=

Solution for (11x+2x^2)-(-7x-3x^2=+4)= equation:

(11x+2x^2)-(-7x-3x^2=+4)=

We move all terms to the left:

(11x+2x^2)-(-7x-3x^2-(+4))=0

We add all the numbers together, and all the variables

(11x+2x^2)-(-7x-3x^2-4)=0

We get rid of parentheses

2x^2+3x^2+11x+7x+4=0

We add all the numbers together, and all the variables

5x^2+18x+4=0

a = 5; b = 18; c = +4;
Δ = b2-4ac
Δ = 182-4·5·4
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{61}}{2*5}=\frac{-18-2\sqrt{61}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{61}}{2*5}=\frac{-18+2\sqrt{61}}{10}
$